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4p^2-39p+27=0
a = 4; b = -39; c = +27;
Δ = b2-4ac
Δ = -392-4·4·27
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-33}{2*4}=\frac{6}{8} =3/4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+33}{2*4}=\frac{72}{8} =9 $
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